The reasonable domain is 0 <= t <= 8 and the reasonable range is 0 <= b <= 10
The domain
The equation of the function is:
b = 5t − 0.625t^2
Set the function to 0
5t − 0.625t^2 = 0
Divide through by 5t
1 − 0.125t = 0
This gives
0.125t = 1
Solve for t
t = 8
This means that the reasonable domain is 0 <= t <= 8
The range
The equation of the function is:
b = 5t − 0.625t^2
Differentiate the function and set to 0
5 − 1.25t = 0
Evaluate the like terms
1.25t = 5
Solve for t
t = 4
Substitute t = 4 in b = 5t − 0.625t^2
b = 5 * 4 − 0.625 * 4^2
Evaluate
b = 10
Hence, the reasonable range is 0 <= b <= 10
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