The volume of CO₂ gas produced is 34.8 liters.
The chemical reaction stating decomposition of CaCO₃ is -
CaCO₃ → CaO + CO₂
In the above reaction, CaCO₃ is calclium carbonate, CaO represents calcium oxide and CO₂ is the chemical formula of carbon dioxide.
In the reaction, 1 mole of CaCO₃ forms 1 mole of CO₂. So, number of moles of CaCO₃ consumed will be equal to number of moles of CO₂ produced.
Molar mass of CaCO₃ = 100.1 grams/mole
Number of moles = [tex]\frac{45}{100.1}[/tex]
Number of moles = 0.44955 moles
Now, using ideal gas equation to find the volume of CO₂ produced at STP.
PV = nRT, where P is pressure in atm, V is volume in liters, n is number of moles, R is gas constant and T is temperature in Kelvin.
Taking R = 0.0821 L-atm per mol-K
Also, 1 torr = 0.00132 atm
So, 645 torr = 0.00132*645
645 torr = 0.8487 atm
Keep the values in formula to find Volume.
[tex]V = \frac{0.44955*0.0821*800}{0.8487}[/tex]
V = 34.8 liters
Hence, the volume of CO₂ gas produced is 34.8 liters
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