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It takes a car 6.4 s to stop after the driver starts braking from a velocity of 32 m/s. The deceleration is at a rate of -5.0 m/s^2. How far will the car travel before it stops?

Respuesta :

The distance the car will travel before it stops is 102.4 m.

Distance traveled by the car

The distance traveled by the car is calculated as follows;

s = ut + ¹/₂at²

where;

  • u is initial velocity of the car
  • a is deceleration of the car
  • s is the distance traveled by the car
  • t is time of motion

substitute the given parameter and solve for distance traveled by the car.

s = (32 x 6.4) + (0.5)(-5)(6.4²)

s = 102.4 m

Thus, the distance the car will travel before it stops is 102.4 m.

Learn more about distance traveled by car here: https://brainly.com/question/26670981

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