The mass of a lead ball with a radius of 0.50 mm is: 5.96904*10^-3 g
To solve this problem the formulas and the procedures that we have to use are:
- v(sphere)= (4 *π * r³) / 3
- d = m/v
Where:
- v= volume
- π = mathematical constant
- r = radius
- d= density
- m= mass
Information about the problem:
- d = 11.4 g/cm3
- r= 0.50 mm
- π = 3.1416
- m=?
- v=?
By converting radius’ units from millimeters to centimeters we have:
r= 0.50 mm * 1 cm/10 mm
r= 0.05 cm
Using the volume of a sphere formula we get:
v(sphere)= (4 *π * r³) / 3
v(sphere)= (4 *3.1416 * (0.05 cm )³) / 3
v(sphere)= (4 *3.1416 * 1.25*10^-4 cm³) / 3
v(sphere)= (1.5708*10^-3 cm³) / 3
v(sphere)= 5.236*10^-4 cm³
Applying the density formula and clearing the mass we get:
d = m/v
m= d * v
m= 11.4 g/cm3 * 5.236*10^-4 cm³
m = 5.96904*10^-3 g
What is volume?
It is the space occupied by a body, it is calculated by multiplying its dimensions, for example: length, height and width.
Learn more about volume in brainly.com/question/12628341
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