The molarity of the solution is 7.704 M.
Given,
Mass of solute (ammonium nitrate) = 154.2 g
Volume of solution = 250 ml = 0.25 L
Molar mass of ammonium nitrate = 80.043 g/mol
Number of moles of solute = 154.2/80.043
= 1.926 moles
Molarity = number of moles of solute/ volume of solution
= 1.926/0.25
=7.704 M
Hence, the molarity of the solution is 7.704 M.
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