The solutions of the equation are x = 3 and x = -6
How to determine the solutions of the equation?
The equation is given as:
the absolute value quantity four thirds times x plus 2 end quantity minus 6 equals 0
Rewrite the equation properly as:
|4/3x + 2| - 6 = 0
Add 6 to both sides
|4/3x + 2| = 6
Remove the absolute bracket
4/3x + 2 = 6 and 4/3x + 2 = -6
Subtract 2 from both sides
4/3x = 4 and 4/3x = -8
Solve for x
x = 3 and x = -6
Hence, the solutions of the equation are x = 3 and x = -6
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