Four cups of pure water are added to a 20-cup bowl of punch that is 75% juice. What percentage of the new punch is juice? Original (Cups) Added (Cups) New (Cups) Amount of Juice 15 0 Amount of Punch 20 4 27% 37.5% 62.5% 75%

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The required percentage of the new punch is 62.5. Option C is correct.

Given that,
Four cups of pure water are added to a 20-cup bowl of punch that is 75% juice.

here,
The quantity of water added = 4 cups
The initial quantity of water = 20 * 25/100 = 5 cups
Now, quantity of punch = 4 + 20 = 24 cups
The initial composition of juice is 75% intially
Quantity of juice initally = 20 * 75/100 = 15 cups
Now, the composition of juice after adding 4 cups of water,
= 15 / 24*100
= 62.5%

Thus. the required percentage of the new punch is 62.5. Option C is correct.

Learn more about ratios here:

brainly.com/question/13419413

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