In the figure shown, m∠THV=(16x+20)∘, m∠THX=53∘, and m∠XHV=(12x−9)∘. What is the value of x? Enter your answer in the box.

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In the figure shown mTHV16x20 mTHX53 and mXHV12x9 What is the value of x Enter your answer in the box x class=

Respuesta :

The value of x is 6.

Given,

m∠THV=(16x+20)

m∠THX=53

m∠XHV=(12x−9)

We need to find what is the value of x.

In the given figure we see that.

m∠THV = m∠THX + m∠XHV

Substituting the given:

m∠THV=(16x+20)

m∠THX=53

m∠XHV=(12x−9)

m∠THV = m∠THX + m∠XHV

(16x+20) = 53 + (12x−9)

16x + 20 = 53 + 12x - 9

Subtracting 12x on both sides

16x + 20 - 12x = 53 + 12x - 9 - 12x

4x + 20 = 53 - 9

4x + 20 = 44

Subtracting 20 on both sides

4x + 20 - 20 = 44 - 20

4x = 24

Dividing 4 on both. sides

4x/4 = 24/4

x = 6.

We see that x = 6.

Thus the value of x is 6.

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