∑Hey , jillianwagler ⊃
Answer:
x=2,y=5
Step-by-step explanation:
Given:
Solve the system below using substution
{2x-3y= -11}
{2x+y=9}
Solution~:
[tex]\begin{bmatrix}2x-3y=-11\\ 2x+y=9\end{bmatrix}[/tex]
Isolate x for 2x-3y = -11 : [tex]x=\frac{-11+3y}{2}[/tex]
Substitute [tex]x=\frac{-11+3y}{2}[/tex] to:
[tex]\begin{bmatrix}2\cdot \frac{-11+3y}{2}+y=9\end{bmatrix}[/tex]
= [tex]\begin{bmatrix}-11+4y=9\end{bmatrix}[/tex]
Isolate y for -11 + 4y = 9 : y = 5
Substitute y = 5
[tex]x=\frac{-11+3\cdot \:5}{2}=2[/tex]
x = 2
Hence, the solutions for [tex]\begin{bmatrix}2x-3y=-11\\ 2x+y=9\end{bmatrix}[/tex] are:
[tex]x=2,\:y=5[/tex]
xcookiex12
8/19/2022
