The value of x assuming that a ≠ 0 in the given equation is 1/a
From the question, we are to determine the value of x assuming that a ≠ 0
The given equation is
4ax + 5ax = 3ax + 6
To solve for x,
First, collect like terms
4ax + 5ax - 3ax = 6
Now, simplify further
9ax - 3ax = 6
6ax = 6
Now, divide both sides of the equation by 6a
6ax / 6a = 6/6a
x = 1/a
Hence, the value of x in the given equation is 1/a
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