∑ Hey, jillianwagler ⊃
Answer:
643
Step-by-step explanation:
Given:
[tex]\mathrm{3x- \frac{x}{2} +4y 2y^3}[/tex]
[tex]\mathrm{x=-2\;and\;y=3}[/tex]
Solve:
Substitute x = - 2 and y = 3
[tex]3\left(-2\right)-\frac{-2}{2}+4\left(3\right)\cdot \:2\left(3\right)^3[/tex]
[tex]\mathrm{Simplify \frac{-2}{2}:1}[/tex]
[tex]=3\left(-2\right)-\left(-1\right)+4\cdot \:3\cdot \:2\cdot \:3^3[/tex]
Following the PEMDAS:
- parenthesis
- exponents
- multiplication
- division
- addition
- subtraction
[tex]\mathrm{3^3:27}[/tex]
[tex]=3\left(-2\right)-\left(-1\right)+4\cdot \:3\cdot \:2\cdot \:27[/tex]
Multiply :
[tex]=-6-\left(-1\right)+4\cdot \:3\cdot \:2\cdot \:27[/tex]
[tex]=-6-\left(-1\right)+648[/tex]
Adding and Subtracting:
[tex]=643[/tex]
xcookiex12
8/19/2022
