The triangle ABC is BC 6.3 cm and AC 7.5 cm. From a point D on AB, a transversal is drawn parallel to the side BC. The transversal meets AC at point E. The distance AE is 2.5 cm. Calculate the length of DE (see figure).

Show the whole solution. thanks

The triangle ABC is BC 63 cm and AC 75 cm From a point D on AB a transversal is drawn parallel to the side BC The transversal meets AC at point E The distance A class=

Respuesta :

The measure of the length of DE is 2.1 cm after applying the similarity law for triangles.

What is the similarity law for triangles?

It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.

It is given that:

The triangle ABC is BC 6.3 cm and AC 7.5 cm.

BC = 6.3 cm

AC = 7.5 cm

AE = 2.5 cm

Applying similarity law for triangles:

AC/BC = AE/DE

7.5/6.3 = 2.5/DE

DE = (2.5x6.3)/7.5

DE = 2.1 cm

Thus, the measure of the length of DE is 2.1 cm after applying the similarity law for triangles.

Learn more about the similarity of triangles here:

brainly.com/question/8045819

#SPJ1

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE