The two consecutive integers are 21 and 22.
Two consecutive integer numbers can be written as x and x + 1.
The lesser of these two numbers is x, and we know that it is 10 more than one-half of the greater integer, then we can write:
x = 10 + (x + 1)/2
Now we can solve that equation for x:
x = 10 + (x + 1)/2
2x = 20 + (x + 1)
2x = 21 + x
x = 21
Then the lesser number is x = 21 and the larger number is x + 1 = 22
If you want to learn more about integer numbers:
https://brainly.com/question/2493629
#SPJ1