In the addition problem attached, the letters H = 2, E = 3, A = 9. See the explanation below.
What is the explanation for the above?
In the problem, A depicts a single digit i.e; A < 9.
=> 4H<10
=>H<3
i.e; H should be 1 or 2.
In units column, 4E should have H in units place in the result. i.e; 1 or 2
As 4E is always an even number, H cannot be 1.
=> H = 2
If H = 2, E can be 3 or 8 for 4E to end in 2.
If E = 8, the result will be a three-digit number => E = 3
So if H = 2 and E = 3
A = 9
Therefore, the letters
H = 2,
E = 3, and
A = 9.
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