The equation which shows the number of minutes it will take for the two containers to have same amount of water is 200+4t=0.
Given that container A has 800 ml and water is increasing by 6 ml per minute, container B has 1000 ml and water is increasing by 10 ml per minute.
We are required to find the equation that shows the minutes it will take for the two containers to have the same amount of water.
Water in container A=800 ml
Rate of increase of water in container A=6 ml per minute
Water in container B=1000 ml
Rate of increase of water in container B=10 ml per minute
According to the question the amount of water in both the containers is same.
let the number of minutes be t.
So,the equation will be:
800+6t=1000+10t
1000-800+10t-6t=0
200+4t=0
Hence the equation which shows the number of minutes it will take for the two containers to have same amount of water is 200+4t=0.
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