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An athlete doing push-ups performs 650 kJ of work and loses 425 kJ of heat. What is the change in the internal energy of the athlete? A. -225 kJ B. -1,075 kJ C. 1,075 kJ D. 225 kJ​

Respuesta :

An athlete doing push-ups performs 650 kJ of work and loses 425 kJ of heat.The change in the internal energy of the athlete is -1075 J.

Given data:

- Work done, [tex]$W=650 \mathrm{~kJ}$[/tex]

- Heat losses, [tex]$Q=-425 \mathrm{~kJ}$[/tex]

The expression for the change in internal energy is,

[tex]$\Delta U=Q-W$[/tex]

Substitute the values,

[tex]$\begin{aligned}&\Delta U=-425-650 \\&\Delta U=-1075 \mathrm{~kJ}\end{aligned}$[/tex]

Therefore, the change in internal energy is [tex]$-1075 \mathrm{~kJ}$[/tex].

Hence, the option (B) is the correct option.

What is Internal Energy?

  • Internal energy is defined as the entire amount of energy stored within a system. The internal energy of a system varies with the amount of work and heat applied to and generated by the system.
  • If the system does work, it signifies that the system's internal energy has been reduced. Work done on the system, on the other hand, causes the system to accumulate energy.
  • If, on the other side, the system loses heat, it is also losing energy. If the system gains heat, this implies that it also gains energy.

Learn more about Internal Energy https://brainly.com/question/11278589

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