A sample of argon gas at a pressure of 679 torr and a temperature of 25.3°C, occupies a volume of 554 mL. If the gas is compressed at constant temperature until its pressure is 887 torr, the volume of the gas sample will be
_ mL.

Respuesta :

The new volume of the gas given the data from the question is 424 mL

Data obtained from the question

The following data were obtained from the question:

  • Initial pressure (P₁) = 679 torr
  • Initial volume (V₁) = 554 mL
  • Temperature = constant
  • New pressure (P₂) = 887 torr
  • New volume (V₂) =?

How to determine the new volume

P₁V₁ / T₁ = P₂V₂ / T₂

Since the temperature is constant, we shall apply the Boyle's law equation to obtain the new volume. Detail below

P₁V₁ = P₂V₂

679 × 554 = 887 × V₂

Divide both sides by 887

V₂ = (679 × 554) / 887

V₂ = 424 mL

Thus, the new volume of the gas is 424 mL

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Oseni

The volume of the gas sample will be 424 mL

General gas equation

The general gas equation is mathematically expressed as:

p1v1/t1 = p2v2/t2

Where p1 and p2 = initial and final pressure, v1 and v2 = initial and final volume, and t1 and t2 = initial and final temperatures.

In this case, p1 = 679 torr,  v1 = 554 mL, t1 = t2 = 25.3 °C = 298.3 K, p2 = 887 torr

Substituting these values into the general gas equation to get the final volume of the gas. We have:

v2 = p1v1t2/t1p2 = 679 x 554/ 887 = 424 mL

Therefore, the new volume of the gas is 424 mL.

More on the general gas equation can be found here: https://brainly.com/question/15207742

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