The alpha decay equation for the following isotope 237/90 Th is as follows:
237/90Th = 233/88U + 4/2He
Alpha decay is the radioactive decay that involves the emission of an alpha particle.
An alpha particle has a positively charged nucleus of a helium-4 atom (consisting of two protons and two neutrons) i.e. 4/2He.
This means that if a radioactive material undergoes alpha decay, 4 will be subtracted from the mass number and 2 from the atomic number.
237/90Th = 233/88U + 4/2He
Therefore, the alpha decay equation for the following isotope 237/90 Th is as follows:
237/90Th = 233/88U + 4/2He
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