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A bottle containing an unknown liquid is either 2-pentanone or 3-pentanone. What is the best methodology to distinguish one compound from the other?

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A bottle containing an unknown liquid is either 2-pentanone or 3-pentanone in which the best methodology is 13C NMR Spectroscopy

What is 13C NMR Spectroscopy?

All the carbon nucleus resonates at a different frequency range than the proton, all of the signals can be singlets.

  • However, signal splitting by nearby hydrogens does occur in 13C NMR, resulting in intricate splitting patterns.
  • As a result, a method known as broadband decoupling is employed. The majority of 13C NMR spectra you will observe are disconnected.
  • You might be wondering why nearby carbons don't produce splitting because they resonate in the same frequency range.
  • Because of the low quantity of the 13C isotope, carbon-carbon coupling is not detected.
  • Remember that the most common natural isotope of carbon, 12C, has an even number of protons and neutrons.

Learn more about 13C NMR Spectroscopy here, https://brainly.com/question/17841943

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