The probability that all 4 computers with the critical file fail in this incident
P(x=4)=0.00085
This is further explained below.
What is the probability that all 4 computers with the critical file fail in this incident?
Generally, is mathematically given as
[tex]$H \rightarrow(n, m)$[/tex]
p.d.F. of Hyper Geometric distribution
given, $N=39, n=4, M=8, x=4$
[tex]\begin{aligned}P(x=4) &=\frac{8}{4} \frac{39}{39} \\&=\frac{70 \times 1}{82251}\end{aligned}$[/tex]
[tex]\begin{aligned}&P(x=4)=8.5106 \times 10^{-4} \\&P(x=4)=0.00085\end{aligned}[/tex]
In conclusion, P(x=4)=0.00085
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