Points a and b are on opposite sides of a lake. a point c is 105.6 meters from a. the measure of angle bac is 70.5 , and the measure of angle acb is 38.83 . find the distance between points a and b (to the nearest meter).

Respuesta :

Answer:

The distance between points a and b in a triangle shape is 70.17 m

Step-by-step explanation:

  • Step 1 Explanation and Formula

Triangle is a special shape that has the rule that the total angle in the triangle should be 180⁰

A + B + C = 180⁰

where A, B, and C are the angles in the triangle.

Moreover, the triangle has a sine rule which shows the relationship between sides and angles. It is given as :

a/sinA = b/sinB = c/sinC

From the question above, we know that :

A = 70.5⁰

C = 38.83⁰

b = 105.6 m

  • Step 2 Calculation

It is needed to determine the angle of B

A + B + C = 180⁰

70.5⁰ + B + 38.83⁰ = 180⁰

B = 70.67⁰

Then, determine the distance between points a and b (c) by using the sine rule

b/sinB = c/sinC

105.6 / sin(70.67⁰) = c / sin(38.83⁰)

105.6 / 0.94 = c / 0.63

c = 70.17 m

Hence, the distance between points a and b is 70.17 m

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