Solve for x. one third times the absolute value of the quantity x minus 3 end quantity plus 4 equals 10 x = −15 and x = 21 x = −5 and x = −1 x = 1 and x = 5 x = 15 and x = 21

Respuesta :

The solution for the absolute value equation is option (A) x = -15 and x = 21 is the correct answer.

In this question,

One third times the absolute value of the quantity x minus 3 end quantity plus 4 equals 10. The equation for this statement is 1/3  |x - 3| + 4 = 10.

The solution for the equation is

[tex]\frac{1}{3}[/tex]  |x - 3| + 4 = 10

⇒ [tex]\frac{1}{3}[/tex] |x - 3| = 10 - 4

⇒ [tex]\frac{1}{3}[/tex] |x - 3| = 6

Multiply by 3 on both sides,

⇒ [tex]\frac{1}{3}[/tex] |x - 3| = 6

⇒ [tex]\frac{3}{3}[/tex] |x - 3| = 18

The absolute value of the equation takes both as positive and negative values.

Case 1: Take as positive value

⇒ x - 3 = 18

⇒ x = 18 + 3

⇒ x = 21

Case 2: Take as negative value

⇒ - (x-3) = 18

⇒ -x + 3 = 18

⇒ x = 3 - 18

⇒ x = -15

Hence we can conclude that the solution for the absolute value equation is option (A) x = -15 and x = 21 is the correct answer.

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