Considering the perimeter of the rectangle, it is found that the length of the rectangle is of 22 in and the width is of 16 in.
The perimeter of a rectangle of length l and width w is given by:
P = 2(l + w).
For this problem, the length is 6 in longer than the width, hence:
l = 6 + w.
The perimeter of the rectangle is of 76 in, hence:
P = 76.
Since l = 6 + w:
2(l + w) = 76
l + w = 38
6 + w + w = 38
2w = 32
w = 16.
Then the length is given by:
l = 6 + w = 6 + 16 = 22 in.
The length of the rectangle is of 22 in and the width is of 16 in.
More can be learned about the perimeter of a rectangle at https://brainly.com/question/10489198
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