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In a high-quality coaxial cable, the power drops by a factor of 10 approximately every 2.75 km. If the original signal power is 0.45 W (= 4.5 x 10-1), how far will a signal be transmitted before the power is attenuated to 45 μW?
Include a table showing the signal power (in W) vs distance in 2.75 km intervals (like Table 1.2 in Section 1.4.4) as part of your answer.

If optical fibre is used instead of the coaxial cable, briefly explain how you would expect the above calculated distance value to change (see Section 1.4.4). You are not required to include another table for this last part.

Respuesta :

8.25 kilometers will be covered by the signal before its strength is reduced to 45 microwatts due to the attenuation that occurs with distance.

What is electric power?

The combination of voltage and current results in the production of electric power. One watt is equal to one of these. It refers to the speed at which the electric task is completed.

Given condition;

Approximately every 2.75 kilometers, power decreases by a factor of ten.

0.45 W -> 0 km

0.045 W -> 2.75 km

0.0045 W -> 5.5 km

0.00045 W -> 8.25 km

0.00045W = 0.45 mW = 45 uW -> 8.25 km

As a result, 8.25 kilometers is going to be the maximum distance that a signal may be delivered before its strength is reduced to 45 microwatts.

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