During the first seconds after takeoff, a rocket traveled 208 kilometers in 50 minutes at a constant rate. Suppose a penny is dropped from a skyscraper and could travel 153 kilometers in 1/2 hour at a constant rate . Which of these objects has a faster unit per hour? How much faster.

Respuesta :

The object penny has a faster unit per hour than the rocket. It is faster at 56.4 km/h. Using the speed-distance-time relation, the required value is calculated.

What is the speed-distance-time relation?

The speed-distance-time relation is given by the formula:

speed = distance/time

Units: distance - m or km; time - sec or min or hours; speed - m/sec or km/hours

Calculation:

It is given that,

A rocket travels 208 km in 50 minutes and a penny is dropped from a skyscraper and traves 153 km in 20 minutes.

So,

The speed of the rocket is

Rs = distance traveled by rocket/time taken to travel

    = 208/50

    = 4.16 km/minutes

The speed of the penny is

Ps = distance traveled by penny/time taken to travel

    = 153/20

    = 5.1 km/minutes

Converting into km/hour:

Rs = 4.16 km/min = 4.16 × 60/hour = 249.6 km/hour

Ps = 5.1 km/min = 5.1 × 60/hour = 306 km/hour

Therefore, the penny has more speed than the rocket.

The penny is faster than a rocket by the speed

= 306 - 249.6 = 56.4 km/h

Hence, the penny is faster by 56.4 km/h.

Learn more about the speed formula here:

https://brainly.com/question/3004254

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