A spaceship with a constant speed of 0.800c relative to earth travels to a star that is 4.30 light-years from earth. How much time for this trip would elapse on a clock on board the spaceship?

Respuesta :

The time elapsed is 3.23 years.

To find the time elapsed, we will begin with calculation of distance traveled. Subsequently we will calculate time elapsed.

The formula to be used for finding out the distance traveled is -

[tex]x_{0} =[/tex] [tex]x\sqrt{1-\frac{v^{2}}{c^{2} } }[/tex]

In this formula, x₀ represents distance traveled, x represents distance measured at Earth, v is spaceship velocity and c is speed of light. Now, keeping the values in formula to find the value of distance traveled.

[tex]x_{0} =4.3\sqrt{1-\frac{(0.8c)^{2} }{c} }[/tex]

[tex]x_{0} =4.3\sqrt{0.36 }[/tex]

[tex]x_{0} = 2.58[/tex] light years

Now, we know the distance traveled. Also, distance and time are related to each other by the formula -

[tex]Speed = \frac{distance}{time}[/tex]

Speed of spaceship = 0.8c

Distance traveled = 2.58 light years

Again keep the values in formula to find the time elapsed.

Time = [tex]\frac{2.58}{0.8c}[/tex]

Time = 3.23 years

Hence, 3.23 years would elapse on a clock on board the spaceship.

Practice more problems on light years -

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