The current should change at a rate of 500A/s
To calculate the rate of change of current, we are using the formula here,
E= L[tex]\frac{\triangle I}{\triangle t}[/tex]
Or, [tex]\frac{\triangle I}{\triangle t}[/tex]= [tex]\frac{E}{L}[/tex]
We are given here,
E = The generating emf.
= 2.0 V
L= The inductance of an ideal solenoid.
= 4.0 mH = 4.0× 10⁻³ H.
We have to calculate the rate of change of current = [tex]\frac{\triangle I}{\triangle t}[/tex]
Now we put the known values in the above equation, we can get,
[tex]\frac{\triangle I}{\triangle t}[/tex]= [tex]\frac{E}{L}[/tex]
Or, [tex]\frac{\triangle I}{\triangle t}[/tex] = [tex]\frac{2.0}{4.0\times 10^{-3}}[/tex]
Or, [tex]\frac{\triangle I}{\triangle t}[/tex]= 500 A/s.
From the above calculation we can surely conclude that, the current should change at a rate of 500A/s.
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