Solve y = ax² + c for x.
O x
x= ± √ay-c
O
O
x = ±₁
X=
X=
у-с
a
y
y + c
a

In the quadratic equation y = a[tex]x^{2}[/tex] + c ,the value of x = ± [tex]\sqrt \frac{y-c}{a}[/tex]
A quadratic equation is any equation containing one term wherein the unknown is squared and no term wherein it's far raised to a higher power.
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, in which a and b are the coefficients, x is the variable, and c is the constant term.
To find the value of x
Assuming [tex]a\neq o[/tex]
First, subtract c from both the sides to get:
[tex]y-c=ax^{2}[/tex]
then, divide both sides by [tex]a[/tex] and transpose to get:
[tex]x^{2} =\frac{y-c}{a}[/tex]
So, [tex]x[/tex] must be a square root of [tex]\frac{y-c}{a}[/tex] and we can deduce:
[tex]x=[/tex] ± [tex]\sqrt \frac{y-c}{a}[/tex]
Learn more about quadratic equations here brainly.com/question/1214333
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