suppose that fanf g are continuous functions,
12_(^28 f(x)dx=19, and 12 (^28 g(x)dx =35.
Find
12_ f^28 [kg(x)-2f(x)] dx, where the coefficient
k=7
those are intergral symbols with numbers on
top and bottom. please show work. thanks

suppose that fanf g are continuous functions 1228 fxdx19 and 12 28 gxdx 35 Find 12 f28 kgx2fx dx where the coefficient k7 those are intergral symbols with numbe class=

Respuesta :

The required result based on given continuous functions is: 207. See the explanation for same below.

What are continuous functions?


A continuous function in mathematics is one in which a continuous variation (that is, a change without a jump) of the argument causes a continuous variation of the function's value.

What is the calculation for the above solution?

Since G and F are continuous functions,

[tex]\int_{12}^{28}) \, f(x) dx[/tex] = 19

[tex]\int_{12}^{28}) \, f(x) dx[/tex] = 35

Therefore,

[tex]\int_{12}^{28}) \, [K g(x) - 2 f(x)] dx[/tex]

= K [tex]\int_{12}^{28}) \, g(x) dx -2 \int_{12}^{28}) \, f(x) dx[/tex]

So, given that K = 7, we have

7 x 35 - 2 x 19
= 245 - 38
= 207

Learn more about continuous functions at;
https://brainly.com/question/18102431
#SPJ1

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE