A hydraulic system contains one small piston with a area of 5.33 square inches and one large piston with an area of 10 square inches. If a force of 70 pounds is applied to the small piston, what will the system pressure be

Respuesta :

The pressure of the system is 13 ponds/square inches.

What is the pressure on the system?

The hydraulic press has two arms and the pressure applied on one arm is equal to the pressure applied on the other arm. The force could be given in pounds or Newton.

Hence,

A1 =  5.33 square inches

A 2 = 10 square inches

F1 = 70 pounds

F2 = ?

F2 = F1[A2/A1]

F2 = 70[10/5.33]

F2= 131 pounds

Pressure of the system = 131 + 70/ 10 + 5.33 =  13 ponds/square inches

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