The value of [tex]f^{-1}(49)[/tex] is 4
Inverse of a function
The given function is:
[tex]f(x)=(x+3)^2[/tex]
Let f(x) be represented by y
[tex]y=(x+3)^2[/tex]
Make x the subject of the formula
[tex]\sqrt{y} =x+3[/tex]
Subtract 3 from both sides
[tex]x=\sqrt{y} -3[/tex]
Replace x by [tex]f^{-1}(x)[/tex] and let y be replaced by x
[tex]f^{-1}(x)=\sqrt{x} -3[/tex]
Substitute x = 49 into the inverse function
[tex]f^{-1}(x)=\sqrt{49} -3\\\\f^{-1}(x)=7-3\\\\f^{-1}(x)=4[/tex]
Learn more on inverse functions here:https://brainly.com/question/3831584
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