contestada

Given: NM 1 XZ
Prove: AXYZ- ANYM
N
Try 11
X
Z
M
We know that side NM is
to side
XZ. If we consider side NY the transversal for these
parallel lines, we create angle pairs. Using the
we can state
that YXZ is congruent to YNM. We know that angle
XYZ is congruent to angle
by the reflexive
property. Therefore, triangle XYZ is similar to triangle
NYM by the
similarity theorem.
F

Given NM 1 XZ Prove AXYZ ANYM N Try 11 X Z M We know that side NM is to side XZ If we consider side NY the transversal for these parallel lines we create angle class=

Respuesta :

Martebi

The prove of  Angle XYZ- Angle NYM is given below:

  • ∠XYZ is congruent to ∠NYM - reflexive property.
  • ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.

What is the triangle about?

Note that from the image given;

  • NM // XZ
  • NY = transversal line
  • ∠YXZ ≡ ∠YNM

Since ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.

The reflexive property is one that informs that any shape is regarded congruent to itself.

Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.

Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.

Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.

We have 2 angles Δ XYZ and Δ NYM:

Note that ∠YXZ ≡ ∠YNM

              ∠XYZ ≡ ∠NYM

So,  ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.

Therefore, The prove of  Angle XYZ- Angle NYM is given below:

  • ∠XYZ is congruent to ∠NYM - reflexive property.
  • ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.

Learn more about triangles from

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