The concentration of the final solution will be 0.2886 M.
Molar concentration
50.6 g of NaCl is dissolved in 600 mL of water.
Mole of 50.6 g NaCl = 50.6/58.44 = 0.8658 mol
Molar concentration of the oiriginal solution = 0.8658/06 = 1.4431 M
25 mL of 1.4431 M of the solution is diluted up to the 125 mL mark.
m1 = 1.4431, v1 = 25 ml, v2 = 125 mL
m2 = m1v1/v2 = 1.4431 x 25/125 = 0.2886 M
The concentration of the final solution will be 0.2886 M
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