Based on the given codewords, and the Hamming pairwise distances, the minimum hamming distance for the parts are:
What are the Hamming pairwise distances?
The hamming distance for part A:
a.. 00000 - 10101 = 3
b. 00000 - 01010 = 2
c. 10101 - 01010 = 5
The minimum hamming distance seen is 2.
A short way to find the distance is to count the number of 1s.
For part B, the hamming distances are:
a. 000000 - 010101 = 3
b. 000000 - 101010 = 3
c. 000000 - 110110 = 4
d. 010101 - 101010 = 6
e. 010101 - 110110 = 3
f. I101010 - 110110 = 3
We can therefore see that the minimum hamming distance is 3.
Find out more on pairwise combinations at https://brainly.com/question/15083704.
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