If the marriage licenses issued in 2001,2003,2006,2010 were 141000,133000,121000,141000 then by solving arithmetic progression we will get that the marriage licenses issued in 2008 were 113000.
Given that the marriage licenses issued in 2001,2003,2006,2010 were 141000,133000,121000,141000.
We are required to find how many marriage licenses were issued in 2008.
Average difference between licenses issued from 2001 to 2003=
=133000-141000)/2
=-4000
Average difference between licenses issued from 2003 to 2006=
=(121000-133000)/3
=-12000/3
=-4000
Average difference between licenses issued from 2006 to 2010=
=(105000-121000)/4
=-16000/4
=-4000
It is an arithmetic progression because the difference between marriage issued from one year to another is equal.
An arithmetic progression is a sequence in which each terms are having equal difference between them.
Nth term=a+(n-1)d
8th term=141000+(8-1)*(-4000)
=141000+7*(-4000)
=141000-28000
=113000
Hence the marriage licenses issued in 2008 were 113000 which is
option A.
Learn more about arithmetic progressions at https://brainly.com/question/6561461
#SPJ1
