The tension on the connecting string of the two blocks is 6 N.
coefficient of friction between the surface and larger block, μ₁ = 0.20
coefficient of kinetic friction between the surface and smaller block, μ₂ = 0.3
horizontal force, F = 10 N
mass of the larger block, m₁ = 2M = 2 kg
mass of the smaller block, m₂ = M = 1 kg
We use the formula below to determine the rate of change of acceleration along the horizontal block
F +μ2Mg - μ1(2M)g = a(M+2M)
10+0.3×1×9.8 - 0.2×2×9.6 = a(1+2)
9.02= 3a
a=9.02/3a
a= 3m/s³
The tension is calculated as T = m₁a
T = 2 x 3
T = 6N
Therefore,
the tension in the connecting string is 6 N.
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As shown below, the coefficient of kinetic friction between the surface and the larger block is 0.20, and the coefficient of kinetic friction between the surface and the smaller block is 0.30. If F = 10N and M = 1.0 kg what is the tension in the connecting string?
