A metallurgist has one alloy containing 39% copper and another containing 65% copper. How many pounds of each alloy must he use to make 48 pounds of a third alloy containing 62% copper? (Round to two decimal places if necessary.)

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The metallurgist must use 5.538 pounds of an alloy with 39 % copper and 42.462 pounds of an alloy with 62 % copper.  

How to calculate proportions of components associated to an alloy

Herein we must create a new alloy by using correct quantities of two alloys with distinct copper concentrations. All required information can be found by concept of weighted averages:

(62/100) · (48 lb) = (39/100) · x + (65/100) · (48 - x)

62 · 48 = 39 · x + 65 · 48 - 65 · x

3 · 48 = 26 · x

x = 5.538 lb

The metallurgist must use 5.538 pounds of an alloy with 39 % copper and 42.462 pounds of an alloy with 62 % copper.  

To learn more on weighted averages: https://brainly.com/question/28053890

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