The minimum number of comparisons to find the smallest number from 5 integers is 4.
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
Read more about Smallest Integer at; https://brainly.com/question/13329614
#SPJ1
