The a28th term of a arithmetic sequence is -242.
According to the statement
We have given that :
a1 = 1 and d = -9. And by use of it we have to find the value of the a28th term in the arithmetic sequence.
So, arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is
an = a1 +(n-1)d
here put the values in it
an = a28 , n = 28, d =-9, a1 =1
then
an = a1 +(n-1)d
a28 = 1 +(28-1)(-9)
a28 = 1 +(27)(-9)
a28 = 1 -243
a28 = -242.
So, The a28th term of a arithmetic sequence is -242.
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