Emma has money in two savings accounts. One rate is 6% and the other is 14%. If she has $950 more in the 14% account and the total interest is $342, how much is invested in each savings account?

Respuesta :

$1045 was invested at the interest rate 6% whereas $1,995 was invested at 14%

How is interest computed?

Interest is determined as the amount invested multiplied by the interest rate.

Let Y be the amount invested at 6%

Interest=Y*6%

Interest=0.06Y

The amount invested at 14%, which is $950 more , is Y+950

Interest=(Y+950)*14%

Interest=0.14Y+133

Total interest =0.06Y+0.14Y+133

Note that total interest is 342

342=0.06Y+0.14Y+133

342=0.20Y+133

342-133=0.20Y

209=0.20Y

Y=209/0.20

Y=$1,045(amount invested at 6%)

Amount invested at 14%=$1,045+$950

Amount invested at 14%=$1,995

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