The mean of the given sample with confidence interval of (61, 85) is; 73
We are given;
Confidence level = 95%
Confidence Interval = (61, 85)
Formula for confidence interval is;
CI = x' ± z(s/√n)
where;
CI is confidence interval
x' is sample mean
s is standard deviation
n is sample size
z is test score at confidence level
Now, for us to find the mean of the sample with a confidence interval of (61, 85), we will just add both and divide by 2 to get;
Mean of population = (61 + 85)/2
Mean of Population = 73
Complete question is;
Suppose that, based on a sample, the 95% confidence interval for the mean of a population is (61,85). What was the mean of the sample?
A.73
B.81
C.69
D.77
Read more about Confidence Interval at; https://brainly.com/question/17097944
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