Johnny picks up a baseball and throws it to Rob who is exactly 130 feet away at a direction of 50 degrees. Rob then throws the ball to Patrick who is 50 feet from Rob in a direction of 30 degrees. Find the exact distance and direction that Patrick is from Johnny.


I need to sketch a triangle.

Respuesta :

The exact distance and direction that Patrick is from Johnny is; 177.81 ft and 215.52°

How to utilize trigonometric ratios?

Let the distance of Johnny to Patrick be x.

The angle opposite x would be; (90 - 50) + 90 + 30 = 160°

We will therefore use the cosine rule to find x;

X² = A² + B² - 2ABcosx

Where;

A and B are the distance of Johnny to Rob and Rob to Patrick respectively. Thus;

X² = 130² + 50² - 2(130)(50)cos160

X²= 16900 + 2500 + 12216.004

X² = 31616.004

X = 177.81 ft

To get the direction "y" we will use sine rule;

50/siny = 177.809/sin160

50/siny = 177.809/0.342

50/siny = 519.9094

Siny = 50/519.904

Siny = 0.09617

y = sin⁻¹(0.09617)

y = 5.52°

The bearing of Patrick from Johnny is;

5.52 + 30 + 180 = 215.52°

Read more about Trigonometric Ratios at; https://brainly.com/question/24349828

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