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The concentration of LiOH in the reaction is 0.103 M
This is a neutralization reaction and the equation of the reaction is written as; H2SO4(aq) + 2LiOH(aq) ---->Li2SO4(aq) + H2O(l)
The average volume of acid used is obtained from;
8.54 + 8.51 + 8.68/ 3 = 8.58 mL
CA = 0.150 M
VA = 8.58 mL
CB = ?
VB= 25.0 mL
NA = 1
NB = 2
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CB = CAVANB/VBNA
CB = 0.150 * 8.58 * 2/25.0 * 1
CB = 0.103 M
The concentration of LiOH in the reaction is 0.103 M
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