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Answer:
[tex]\huge\boxed{\sf n = 49}[/tex]
Step-by-step explanation:
[tex]x^2-14x+n[/tex] ---------------(1)
We need to solve it using the following formula:
[tex]a^2-2ab+b^2=(a-b)^2[/tex]
Writing the middle term in the expression as 2ab
[tex](x)^2-2(x)(7)+n[/tex]
Form the expression, we come to now that
So, the we can write the expression as:
[tex](x)^2-2(x)(7)+(7)^2\\\\x^2-14n+49[/tex]
Comparing expression (1) with the above expression, we get:
[tex]\rule[225]{225}{2}[/tex]