The probability that he can fit through the doorway without bending is 14.92%
We are given;
Mean; μ = 69.5
Standard deviation; σ = 2.4
Sample mean; x' = 72
The standardized score is the value x decreased by the mean and then divided by the standard deviation. Thus;
z = (x' − μ)/σ
z = (72 − 69.5)/2.4
z = 1.04
Using p-value from z-score calculator gives us;
p-value = 0.1492 = 14.92%
Thus, the probability that he can fit through the doorway without bending is 14.92%
Complete Question is;
The Boeing 757-200 ER airliner carries 200 passengers and has doors with a height of 72 in. Heights of men are normally distributed with a mean of 69.5 in. and a standard deviation of 2.4 in. If a male passenger is randomly selected, find the probability that he can fit through the doorway without bending.
Read more about P-value from z-scores at; https://brainly.com/question/25638875
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