The width of the central maximum on the screen is 4.88 mm.
Calculations and Parameters
Given:
Diameter: 0.51 * 10^-3m
Wavelength: 510 * 10^-9 nm
Distance: 2m
θ= 1.22λ /d
x= 2Dθ
= [tex]\frac{(2) (2) (1.22) (510 * 10^-^9m)}{0.51 * 10^-^3}[/tex]
= 4.88 mm.
The complete question is:
A 0.51 mm-diameter hole is illuminated by light of wavelength 510 nm.
What is the width of the central maximum on a screen 2.0 m behind the slit?
Express your answer using two significant figures.
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