pls pls pls helppp
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Answer:
y = 4x^2 + 8x - 12
4(x^2 + 2x - 3) = 0
4(x - 1)(x + 3) = 0
x = 1, -3
Answer:
[tex]\fbox {x-intercepts : (1, 0) and (-3, 0)}[/tex]
[tex]\fbox {Roots : x = 1, x = -3}[/tex]
Step-by-step explanation:
Given :
4 cancels throughout.
Solving by quadratic formula :
∴ Hence, the x-intercepts are (1, 0) and (-3, 0). The roots of the equation are 1 and -3.