Respuesta :

Answer:

y = 4x^2 + 8x - 12

4(x^2 + 2x - 3) = 0

4(x - 1)(x + 3) = 0

x = 1, -3

Answer:

[tex]\fbox {x-intercepts : (1, 0) and (-3, 0)}[/tex]

[tex]\fbox {Roots : x = 1, x = -3}[/tex]

Step-by-step explanation:

Given :

  • y = 4x² + 8x - 12

4 cancels throughout.

  • y = x² + 2x - 4

Solving by quadratic formula :

  • x =  -8 ± √(8)² - 4(4)(-12) / 8
  • x = -8 ± √64 + 192 / 8
  • x = -8 ± √256 / 8
  • x = -8 ± 16 / 8
  • x = -1 ± 2
  • x = 1 and x = -3

∴ Hence, the x-intercepts are (1, 0) and (-3, 0). The roots of the equation are 1 and -3.

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