1. The amount of OH¯ present in the solution is 0.1 mol/L
2. The amount of H⁺ present in the solution is 0.0000000000001 mol/L
3. The pH of the solution with H⁺ concentration of 1×10⁻⁴ mol/L is 4
We'll begin by obtaining the pOH of the solution
pH + pOH = 14
13 + pOH = 14
Collect like terms
pOH = 14 - 13
pOH = 1
Finally, we can determine the OH¯
pOH = –Log [OH¯]
1 = –Log [OH¯]
Multiply through by –1
–1 = Log [OH¯]
Take the anti-log of –1
[OH¯] = anti-log of (–1)
[OH¯] = 0.1 mol/L
pH = –Log [H⁺]
13 = –Log [OH¯]
Multiply through by –1
–13 = Log [H⁺]
Take the anti-log of –13
[H⁺] = anti-log of (–13)
[H⁺] = 0.0000000000001 mol/L
pH = –Log [H⁺]
pH = –Log 1×10⁻⁴
pH = 4
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