Answer:
[tex]\sf 1\dfrac{2}{5} \ cm[/tex]
Step-by-step explanation:
If two sides of the triangle are equal, then the triangle is called isosceles triangle.
Let the two equal sides = x cm
Perimeter of the triangle = [tex]\sf 4\dfrac{2}{15}[/tex] cm
[tex]\sf x + x + \dfrac{4}{3}=4\dfrac{2}{15}\\\\[/tex]
[tex]\sf 2x +\dfrac{4}{3}=\dfrac{62}{15}[/tex]
[tex]\sf 2x = \dfrac{62}{15}-\dfrac{4}{3} \ [\text{\bf LCM of 15 , 3 = 15}]\\\\2x = \dfrac{62}{15}-\dfrac{4*5}{3*5}\\\\2x = \dfrac{62}{15}-\dfrac{20}{15}\\\\2x = \dfrac{42}{15} \ [\text{\bf Divide both sides by 2}]\\\\ x = \dfrac{42}{15*2}\\\\ x = \dfrac{7}{5}\\\\ x = 1\dfrac{2}{5}[/tex]
[tex]\sf \boxed{\text{Equal sides of isosceles triangle = $1\dfrac{2}{5}$ cm}}[/tex]