The solution and extraneous solution of the equation as given are; x=7 and x=-2 respectively.
What is the solution of the equation?
It follows that the equation given is;
(3/(x²+5x+6)) + ((x-1)/(x+2)) = 7/(x+3)
Hence, by multiplying both sides by (x²+5x+6); we have;
3 + x² +2x -3 = 7x + 14.
x²-5x -14 = 0
On this note, the solutions of the quadratic equation are; x =7 and x=-2.
It therefore follows that x= 7 is a solution while x=-2 is an extraneous solution because it renders (x-1)/(x+2) undefined.
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